Base | Representation |
---|---|
bin | 1010011001011101000011… |
… | …1100101010111011010101 |
3 | 1111110221001120000111012200 |
4 | 2212113100330222323111 |
5 | 2444302040331240203 |
6 | 40151551150235113 |
7 | 2256651602502162 |
oct | 246272074527325 |
9 | 44427046014180 |
10 | 11432413540053 |
11 | 3708506445740 |
12 | 13478181b5a99 |
13 | 64c0c217409c |
14 | 2b7490529069 |
15 | 14c5b3a299a3 |
hex | a65d0f2aed5 |
11432413540053 has 48 divisors (see below), whose sum is σ = 18103074575040. Its totient is φ = 6894800640000.
The previous prime is 11432413539983. The next prime is 11432413540069. The reversal of 11432413540053 is 35004531423411.
11432413540053 is a `hidden beast` number, since 1 + 1 + 4 + 3 + 241 + 3 + 5 + 400 + 5 + 3 = 666.
It is not a de Polignac number, because 11432413540053 - 212 = 11432413535957 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11432413547053) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 26949493 + ... + 27370421.
It is an arithmetic number, because the mean of its divisors is an integer number (377147386980).
Almost surely, 211432413540053 is an apocalyptic number.
It is an amenable number.
11432413540053 is a deficient number, since it is larger than the sum of its proper divisors (6670661034987).
11432413540053 is a wasteful number, since it uses less digits than its factorization.
11432413540053 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 422290 (or 422287 counting only the distinct ones).
The product of its (nonzero) digits is 86400, while the sum is 36.
Adding to 11432413540053 its reverse (35004531423411), we get a palindrome (46436944963464).
The spelling of 11432413540053 in words is "eleven trillion, four hundred thirty-two billion, four hundred thirteen million, five hundred forty thousand, fifty-three".
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