Base | Representation |
---|---|
bin | 110101001111010101… |
… | …1011000001100110111 |
3 | 101221002221112212222200 |
4 | 1222132223120030313 |
5 | 3333122304234033 |
6 | 124304552555543 |
7 | 11155144123614 |
oct | 1523653301467 |
9 | 357087485880 |
10 | 114331321143 |
11 | 44540060866 |
12 | 1a1a93b2bb3 |
13 | aa20964820 |
14 | 576854150b |
15 | 2e924b7013 |
hex | 1a9ead8337 |
114331321143 has 48 divisors (see below), whose sum is σ = 180772964736. Its totient is φ = 69204041280.
The previous prime is 114331321141. The next prime is 114331321157. The reversal of 114331321143 is 341123133411.
114331321143 is a `hidden beast` number, since 1 + 1 + 4 + 331 + 321 + 1 + 4 + 3 = 666.
It is not a de Polignac number, because 114331321143 - 21 = 114331321141 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (114331321141) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 5406196 + ... + 5427302.
It is an arithmetic number, because the mean of its divisors is an integer number (3766103432).
Almost surely, 2114331321143 is an apocalyptic number.
114331321143 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
114331321143 is a deficient number, since it is larger than the sum of its proper divisors (66441643593).
114331321143 is a wasteful number, since it uses less digits than its factorization.
114331321143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21884 (or 21881 counting only the distinct ones).
The product of its digits is 2592, while the sum is 27.
Adding to 114331321143 its reverse (341123133411), we get a palindrome (455454454554).
The spelling of 114331321143 in words is "one hundred fourteen billion, three hundred thirty-one million, three hundred twenty-one thousand, one hundred forty-three".
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