Base | Representation |
---|---|
bin | 10101010010111100… |
… | …01101110111101111 |
3 | 1002111210121000002121 |
4 | 22221132031313233 |
5 | 141403400031411 |
6 | 5130301133411 |
7 | 553216432600 |
oct | 125136156757 |
9 | 32453530077 |
10 | 11433205231 |
11 | 4937823348 |
12 | 2270b5a267 |
13 | 11028c3ac6 |
14 | 7a6639da7 |
15 | 46db11571 |
hex | 2a978ddef |
11433205231 has 6 divisors (see below), whose sum is σ = 13299851040. Its totient is φ = 9799890156.
The previous prime is 11433205159. The next prime is 11433205237. The reversal of 11433205231 is 13250233411.
It is a happy number.
It is not a de Polignac number, because 11433205231 - 29 = 11433204719 is a prime.
It is a super-2 number, since 2×114332052312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11433205196 and 11433205205.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11433205237) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 116665311 + ... + 116665408.
It is an arithmetic number, because the mean of its divisors is an integer number (2216641840).
Almost surely, 211433205231 is an apocalyptic number.
11433205231 is a deficient number, since it is larger than the sum of its proper divisors (1866645809).
11433205231 is an equidigital number, since it uses as much as digits as its factorization.
11433205231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 233330733 (or 233330726 counting only the distinct ones).
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 11433205231 its reverse (13250233411), we get a palindrome (24683438642).
The spelling of 11433205231 in words is "eleven billion, four hundred thirty-three million, two hundred five thousand, two hundred thirty-one".
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