114332535050335 has 16 divisors (see below), whose sum is σ = 166022370225216. Its totient is φ = 73787720099328.

The previous prime is 114332535050329. The next prime is 114332535050347. The reversal of 114332535050335 is 533050535233411.

It is a happy number.

It is a cyclic number.

It is not a de Polignac number, because 114332535050335 - 2⁵ = 114332535050303 is a prime.

It is a super-2 number, since 2×114332535050335² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114332535050291 and 114332535050300.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 96077759952 + ... + 96077761141.

It is an arithmetic number, because the mean of its divisors is an integer number (10376398139076).

Almost surely, 2^{114332535050335} is an apocalyptic number.

114332535050335 is a deficient number, since it is larger than the sum of its proper divisors (51689835174881).

114332535050335 is a wasteful number, since it uses less digits than its factorization.

114332535050335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 192155521122.

The product of its (nonzero) digits is 1215000, while the sum is 43.

The spelling of 114332535050335 in words is "one hundred fourteen trillion, three hundred thirty-two billion, five hundred thirty-five million, fifty thousand, three hundred thirty-five".