11443312103 has 4 divisors (see below), whose sum is σ = 11446488240. Its totient is φ = 11440135968.

The previous prime is 11443312099. The next prime is 11443312117. The reversal of 11443312103 is 30121334411.

11443312103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11443312103 - 2² = 11443312099 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11443317103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1582658 + ... + 1589871.

It is an arithmetic number, because the mean of its divisors is an integer number (2861622060).

Almost surely, 2^11443312103 is an apocalyptic number.

11443312103 is a deficient number, since it is larger than the sum of its proper divisors (3176137).

11443312103 is an equidigital number, since it uses as much as digits as its factorization.

11443312103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3176136.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 11443312103 its reverse (30121334411), we get a palindrome (41564646514).

The spelling of 11443312103 in words is "eleven billion, four hundred forty-three million, three hundred twelve thousand, one hundred three".