1144331430001 has 4 divisors (see below), whose sum is σ = 1144333569652. Its totient is φ = 1144329290352.

The previous prime is 1144331429977. The next prime is 1144331430037. The reversal of 1144331430001 is 1000341334411.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 439302514401 + 705028915600 = 662799^2 + 839660^2 .

It is a cyclic number.

It is not a de Polignac number, because 1144331430001 - 2⁹ = 1144331429489 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1144331430071) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 514015 + ... + 1597771.

It is an arithmetic number, because the mean of its divisors is an integer number (286083392413).

Almost surely, 2^{1144331430001} is an apocalyptic number.

It is an amenable number.

1144331430001 is a deficient number, since it is larger than the sum of its proper divisors (2139651).

1144331430001 is a wasteful number, since it uses less digits than its factorization.

1144331430001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2139650.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1144331430001 its reverse (1000341334411), we get a palindrome (2144672764412).

The spelling of 1144331430001 in words is "one trillion, one hundred forty-four billion, three hundred thirty-one million, four hundred thirty thousand, one".