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11445103133 is a prime number
BaseRepresentation
bin10101010100010111…
…00110101000011101
31002112121222110221122
422222023212220131
5141414421300013
65131404140325
7553422525422
oct125213465035
932477873848
1011445103133
11494350a422
122274b376a5
1311051cb499
147a8055d49
1546ebb1a08
hex2aa2e6a1d

11445103133 has 2 divisors, whose sum is σ = 11445103134. Its totient is φ = 11445103132.

The previous prime is 11445103121. The next prime is 11445103139. The reversal of 11445103133 is 33130154411.

11445103133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5735487289 + 5709615844 = 75733^2 + 75562^2 .

It is a cyclic number.

It is not a de Polignac number, because 11445103133 - 224 = 11428325917 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11445103139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5722551566 + 5722551567.

It is an arithmetic number, because the mean of its divisors is an integer number (5722551567).

Almost surely, 211445103133 is an apocalyptic number.

It is an amenable number.

11445103133 is a deficient number, since it is larger than the sum of its proper divisors (1).

11445103133 is an equidigital number, since it uses as much as digits as its factorization.

11445103133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2160, while the sum is 26.

Adding to 11445103133 its reverse (33130154411), we get a palindrome (44575257544).

The spelling of 11445103133 in words is "eleven billion, four hundred forty-five million, one hundred three thousand, one hundred thirty-three".