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114544104213151 is a prime number
BaseRepresentation
bin11010000010110101100000…
…101001001000101010011111
3120000120022100120022100210201
4122002311200221020222133
5110003142311134310101
61043340500211244331
733061352453160214
oct3202654051105237
9500508316270721
10114544104213151
1133551977740398
1210a1b4b88a96a7
134bbb602678cb2
14203dd6db91b0b
15d3984d295e01
hex682d60a48a9f

114544104213151 has 2 divisors, whose sum is σ = 114544104213152. Its totient is φ = 114544104213150.

The previous prime is 114544104213103. The next prime is 114544104213199. The reversal of 114544104213151 is 151312401445411.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (114544104213103) and next prime (114544104213199).

It is a cyclic number.

It is not a de Polignac number, because 114544104213151 - 221 = 114544102115999 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 114544104213151.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114544104213101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57272052106575 + 57272052106576.

It is an arithmetic number, because the mean of its divisors is an integer number (57272052106576).

Almost surely, 2114544104213151 is an apocalyptic number.

114544104213151 is a deficient number, since it is larger than the sum of its proper divisors (1).

114544104213151 is an equidigital number, since it uses as much as digits as its factorization.

114544104213151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 38400, while the sum is 37.

Adding to 114544104213151 its reverse (151312401445411), we get a palindrome (265856505658562).

The spelling of 114544104213151 in words is "one hundred fourteen trillion, five hundred forty-four billion, one hundred four million, two hundred thirteen thousand, one hundred fifty-one".