Base | Representation |
---|---|
bin | 10000101110010100111… |
… | …110100010101101111101 |
3 | 11001212102121100010112112 |
4 | 100232110332202231331 |
5 | 122312133424104013 |
6 | 2235543305543405 |
7 | 146013425123414 |
oct | 20562476425575 |
9 | 4055377303475 |
10 | 1149255691133 |
11 | 40343a970850 |
12 | 1668974a4b65 |
13 | 844b3593a44 |
14 | 3d8a500847b |
15 | 1ed64d1eba8 |
hex | 10b94fa2b7d |
1149255691133 has 16 divisors (see below), whose sum is σ = 1359860140800. Its totient is φ = 959336947200.
The previous prime is 1149255691127. The next prime is 1149255691159. The reversal of 1149255691133 is 3311965529411.
It is a cyclic number.
It is not a de Polignac number, because 1149255691133 - 240 = 49744063357 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1149285691133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 74940533 + ... + 74955866.
It is an arithmetic number, because the mean of its divisors is an integer number (84991258800).
Almost surely, 21149255691133 is an apocalyptic number.
It is an amenable number.
1149255691133 is a deficient number, since it is larger than the sum of its proper divisors (210604449667).
1149255691133 is a wasteful number, since it uses less digits than its factorization.
1149255691133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 149896468.
The product of its digits is 874800, while the sum is 50.
The spelling of 1149255691133 in words is "one trillion, one hundred forty-nine billion, two hundred fifty-five million, six hundred ninety-one thousand, one hundred thirty-three".
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