115004200037 has 2 divisors, whose sum is σ = 115004200038. Its totient is φ = 115004200036.

The previous prime is 115004199971. The next prime is 115004200039. The reversal of 115004200037 is 730002400511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 71527362916 + 43476837121 = 267446^2 + 208511^2 .

It is an emirp because it is prime and its reverse (730002400511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 115004200037 - 2¹⁶ = 115004134501 is a prime.

Together with 115004200039, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 115004199985 and 115004200021.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115004200039) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57502100018 + 57502100019.

It is an arithmetic number, because the mean of its divisors is an integer number (57502100019).

Almost surely, 2^115004200037 is an apocalyptic number.

It is an amenable number.

115004200037 is a deficient number, since it is larger than the sum of its proper divisors (1).

115004200037 is an equidigital number, since it uses as much as digits as its factorization.

115004200037 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 840, while the sum is 23.

Adding to 115004200037 its reverse (730002400511), we get a palindrome (845006600548).

The spelling of 115004200037 in words is "one hundred fifteen billion, four million, two hundred thousand, thirty-seven".