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11503055141 = 103111680147
BaseRepresentation
bin10101011011010001…
…01011000100100101
31002200200000202011022
422231220223010211
5142024240231031
65141234220525
7555025232624
oct125550530445
932620022138
1011503055141
1149731a1646
122290424745
13111420c206
147b1a1d6bb
15474d0c97b
hex2ada2b125

11503055141 has 4 divisors (see below), whose sum is σ = 11614735392. Its totient is φ = 11391374892.

The previous prime is 11503055129. The next prime is 11503055149. The reversal of 11503055141 is 14155030511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11503055141 - 26 = 11503055077 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11503055141.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11503055149) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55839971 + ... + 55840176.

It is an arithmetic number, because the mean of its divisors is an integer number (2903683848).

Almost surely, 211503055141 is an apocalyptic number.

It is an amenable number.

11503055141 is a deficient number, since it is larger than the sum of its proper divisors (111680251).

11503055141 is a wasteful number, since it uses less digits than its factorization.

11503055141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 111680250.

The product of its (nonzero) digits is 1500, while the sum is 26.

Adding to 11503055141 its reverse (14155030511), we get a palindrome (25658085652).

The spelling of 11503055141 in words is "eleven billion, five hundred three million, fifty-five thousand, one hundred forty-one".

Divisors: 1 103 111680147 11503055141