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11504440103 = 13886199871
BaseRepresentation
bin10101011011011011…
…11101001100100111
31002200202122002222012
422231231331030213
5142030114040403
65141324024435
7555043061462
oct125555751447
932622562865
1011504440103
114973a58142
12229099211b
1311145a5710
147b1ca02d9
15474ed2ed8
hex2adb7d327

11504440103 has 8 divisors (see below), whose sum is σ = 12390919296. Its totient is φ = 10618178400.

The previous prime is 11504440097. The next prime is 11504440147. The reversal of 11504440103 is 30104440511.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11504440103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11504445103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 65258 + ... + 165128.

It is an arithmetic number, because the mean of its divisors is an integer number (1548864912).

Almost surely, 211504440103 is an apocalyptic number.

11504440103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

11504440103 is a deficient number, since it is larger than the sum of its proper divisors (886479193).

11504440103 is an equidigital number, since it uses as much as digits as its factorization.

11504440103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 108745.

The product of its (nonzero) digits is 960, while the sum is 23.

Adding to 11504440103 its reverse (30104440511), we get a palindrome (41608880614).

The spelling of 11504440103 in words is "eleven billion, five hundred four million, four hundred forty thousand, one hundred three".

Divisors: 1 13 8861 99871 115193 1298323 884956931 11504440103