Base | Representation |
---|---|
bin | 110101100100110001… |
… | …0001011110100001101 |
3 | 101222222001111101122101 |
4 | 1223021202023310031 |
5 | 3341110341101110 |
6 | 124504155515101 |
7 | 11212024452502 |
oct | 1531142136415 |
9 | 358861441571 |
10 | 115050331405 |
11 | 44879a04919 |
12 | 1a36a158a91 |
13 | ab068cb999 |
14 | 57d5c274a9 |
15 | 2ed569213a |
hex | 1ac988bd0d |
115050331405 has 4 divisors (see below), whose sum is σ = 138060397692. Its totient is φ = 92040265120.
The previous prime is 115050331391. The next prime is 115050331421. The reversal of 115050331405 is 504133050511.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 504133050511 = 1979 ⋅254741309.
It can be written as a sum of positive squares in 2 ways, for example, as 43355984841 + 71694346564 = 208221^2 + 267758^2 .
It is not a de Polignac number, because 115050331405 - 25 = 115050331373 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11505033136 + ... + 11505033145.
It is an arithmetic number, because the mean of its divisors is an integer number (34515099423).
Almost surely, 2115050331405 is an apocalyptic number.
It is an amenable number.
115050331405 is a deficient number, since it is larger than the sum of its proper divisors (23010066287).
115050331405 is an equidigital number, since it uses as much as digits as its factorization.
115050331405 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23010066286.
The product of its (nonzero) digits is 4500, while the sum is 28.
Adding to 115050331405 its reverse (504133050511), we get a palindrome (619183381916).
The spelling of 115050331405 in words is "one hundred fifteen billion, fifty million, three hundred thirty-one thousand, four hundred five".
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