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1150540151 is a prime number
BaseRepresentation
bin100010010010011…
…1101100101110111
32222011221111101012
41010210331211313
54324014241101
6310100022435
740340300315
oct10444754567
92864844335
101150540151
115404a4932
12281391a1b
13154497bb7
14acb370b5
156b01abbb
hex4493d977

1150540151 has 2 divisors, whose sum is σ = 1150540152. Its totient is φ = 1150540150.

The previous prime is 1150540141. The next prime is 1150540189. The reversal of 1150540151 is 1510450511.

It is a weak prime.

It is an emirp because it is prime and its reverse (1510450511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1150540151 - 214 = 1150523767 is a prime.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1150540141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575270075 + 575270076.

It is an arithmetic number, because the mean of its divisors is an integer number (575270076).

Almost surely, 21150540151 is an apocalyptic number.

1150540151 is a deficient number, since it is larger than the sum of its proper divisors (1).

1150540151 is an equidigital number, since it uses as much as digits as its factorization.

1150540151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 500, while the sum is 23.

The square root of 1150540151 is about 33919.6130726752. The cubic root of 1150540151 is about 1047.8535595429.

Adding to 1150540151 its reverse (1510450511), we get a palindrome (2660990662).

The spelling of 1150540151 in words is "one billion, one hundred fifty million, five hundred forty thousand, one hundred fifty-one".