Base | Representation |
---|---|
bin | 1101101110001… |
… | …01000110010111 |
3 | 22000120210101212 |
4 | 12313011012113 |
5 | 213431231403 |
6 | 15231012035 |
7 | 2565231434 |
oct | 667050627 |
9 | 260523355 |
10 | 115102103 |
11 | 59a76a06 |
12 | 3266a01b |
13 | 1ab0076c |
14 | 11402b8b |
15 | a1894d8 |
hex | 6dc5197 |
115102103 has 2 divisors, whose sum is σ = 115102104. Its totient is φ = 115102102.
The previous prime is 115102081. The next prime is 115102109. The reversal of 115102103 is 301201511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 115102103 - 210 = 115101079 is a prime.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115102109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57551051 + 57551052.
It is an arithmetic number, because the mean of its divisors is an integer number (57551052).
Almost surely, 2115102103 is an apocalyptic number.
115102103 is a deficient number, since it is larger than the sum of its proper divisors (1).
115102103 is an equidigital number, since it uses as much as digits as its factorization.
115102103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 30, while the sum is 14.
The square root of 115102103 is about 10728.5648154821. The cubic root of 115102103 is about 486.4382897214.
Adding to 115102103 its reverse (301201511), we get a palindrome (416303614).
The spelling of 115102103 in words is "one hundred fifteen million, one hundred two thousand, one hundred three".
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