11512321403 has 4 divisors (see below), whose sum is σ = 12558896088. Its totient is φ = 10465746720.

The previous prime is 11512321397. The next prime is 11512321411. The reversal of 11512321403 is 30412321511.

11512321403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 11512321403 - 2¹⁴ = 11512305019 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11512321903) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 523287326 + ... + 523287347.

It is an arithmetic number, because the mean of its divisors is an integer number (3139724022).

Almost surely, 2^11512321403 is an apocalyptic number.

11512321403 is a deficient number, since it is larger than the sum of its proper divisors (1046574685).

11512321403 is a wasteful number, since it uses less digits than its factorization.

11512321403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1046574684.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 11512321403 its reverse (30412321511), we get a palindrome (41924642914).

The spelling of 11512321403 in words is "eleven billion, five hundred twelve million, three hundred twenty-one thousand, four hundred three".