Base | Representation |
---|---|
bin | 1010011110000110110110… |
… | …0110011000111011110110 |
3 | 1111202120101112200222102020 |
4 | 2213201231212120323312 |
5 | 3002104243342232210 |
6 | 40252411234254010 |
7 | 2265511536024240 |
oct | 247415546307366 |
9 | 44676345628366 |
10 | 11512351133430 |
11 | 37393a70a77a4 |
12 | 135b207127306 |
13 | 6567c13986b4 |
14 | 2bb2b4c9b090 |
15 | 14e6e17bc770 |
hex | a786d998ef6 |
11512351133430 has 128 divisors (see below), whose sum is σ = 31630978649088. Its totient is φ = 2626877332992.
The previous prime is 11512351133419. The next prime is 11512351133447. The reversal of 11512351133430 is 3433115321511.
It is a junction number, because it is equal to n+sod(n) for n = 11512351133391 and 11512351133400.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 390459469 + ... + 390488951.
It is an arithmetic number, because the mean of its divisors is an integer number (247117020696).
Almost surely, 211512351133430 is an apocalyptic number.
11512351133430 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11512351133430 is an abundant number, since it is smaller than the sum of its proper divisors (20118627515658).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11512351133430 is a wasteful number, since it uses less digits than its factorization.
11512351133430 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 32630.
The product of its (nonzero) digits is 16200, while the sum is 33.
Adding to 11512351133430 its reverse (3433115321511), we get a palindrome (14945466454941).
The spelling of 11512351133430 in words is "eleven trillion, five hundred twelve billion, three hundred fifty-one million, one hundred thirty-three thousand, four hundred thirty".
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