115130021 has 2 divisors, whose sum is σ = 115130022. Its totient is φ = 115130020.

The previous prime is 115130011. The next prime is 115130027. The reversal of 115130021 is 120031511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110460100 + 4669921 = 10510^2 + 2161^2 .

It is an emirp because it is prime and its reverse (120031511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 115130021 - 2¹⁰ = 115128997 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 115129978 and 115130005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115130027) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57565010 + 57565011.

It is an arithmetic number, because the mean of its divisors is an integer number (57565011).

Almost surely, 2^115130021 is an apocalyptic number.

It is an amenable number.

115130021 is a deficient number, since it is larger than the sum of its proper divisors (1).

115130021 is an equidigital number, since it uses as much as digits as its factorization.

115130021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 30, while the sum is 14.

The square root of 115130021 is about 10729.8658425910. The cubic root of 115130021 is about 486.4776150566.

Adding to 115130021 its reverse (120031511), we get a palindrome (235161532).

The spelling of 115130021 in words is "one hundred fifteen million, one hundred thirty thousand, twenty-one".