Base | Representation |
---|---|
bin | 1010011110010001111111… |
… | …1011100010000001110000 |
3 | 1111202212010001110120102021 |
4 | 2213210133323202001300 |
5 | 3002131410303121034 |
6 | 40254024153001224 |
7 | 2265645635446105 |
oct | 247443773420160 |
9 | 44685101416367 |
10 | 11515343020144 |
11 | 373a6a1a26547 |
12 | 135b9010b3214 |
13 | 656b7a19c072 |
14 | 2bb4ba390aac |
15 | 14e8192ac6b4 |
hex | a791fee2070 |
11515343020144 has 80 divisors (see below), whose sum is σ = 23678690734656. Its totient is φ = 5406312038400.
The previous prime is 11515343020087. The next prime is 11515343020151. The reversal of 11515343020144 is 44102034351511.
11515343020144 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (34).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 233566504 + ... + 233615800.
Almost surely, 211515343020144 is an apocalyptic number.
It is an amenable number.
11515343020144 is an abundant number, since it is smaller than the sum of its proper divisors (12163347714512).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11515343020144 is a wasteful number, since it uses less digits than its factorization.
11515343020144 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51314 (or 51308 counting only the distinct ones).
The product of its (nonzero) digits is 28800, while the sum is 34.
Adding to 11515343020144 its reverse (44102034351511), we get a palindrome (55617377371655).
The spelling of 11515343020144 in words is "eleven trillion, five hundred fifteen billion, three hundred forty-three million, twenty thousand, one hundred forty-four".
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