Base | Representation |
---|---|
bin | 1010011110100011011000… |
… | …1011111111010000001000 |
3 | 1111210022011101211211221022 |
4 | 2213220312023333100020 |
5 | 3002220440404301300 |
6 | 40300115320332012 |
7 | 2266202423150432 |
oct | 247506613772010 |
9 | 44708141754838 |
10 | 11520011400200 |
11 | 3741678122586 |
12 | 13607a4614008 |
13 | 65744240b724 |
14 | 2bb8003ab652 |
15 | 14e9de05b285 |
hex | a7a362ff408 |
11520011400200 has 24 divisors (see below), whose sum is σ = 26784026505930. Its totient is φ = 4608004560000.
The previous prime is 11520011400167. The next prime is 11520011400211. The reversal of 11520011400200 is 200411002511.
11520011400200 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 3 ways, for example, as 5666427941476 + 5853583458724 = 2380426^2 + 2419418^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 28800028301 + ... + 28800028700.
Almost surely, 211520011400200 is an apocalyptic number.
11520011400200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11520011400200 is an abundant number, since it is smaller than the sum of its proper divisors (15264015105730).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11520011400200 is a wasteful number, since it uses less digits than its factorization.
11520011400200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57600057017 (or 57600057008 counting only the distinct ones).
The product of its (nonzero) digits is 80, while the sum is 17.
Adding to 11520011400200 its reverse (200411002511), we get a palindrome (11720422402711).
The spelling of 11520011400200 in words is "eleven trillion, five hundred twenty billion, eleven million, four hundred thousand, two hundred".
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