11520031 has 2 divisors, whose sum is σ = 11520032. Its totient is φ = 11520030.

The previous prime is 11520013. The next prime is 11520037. The reversal of 11520031 is 13002511.

Together with previous prime (11520013) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is an emirp because it is prime and its reverse (13002511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11520031 - 2¹¹ = 11517983 is a prime.

It is a super-2 number, since 2×11520031² = 265422228481922, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11519993 and 11520020.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11520037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5760015 + 5760016.

It is an arithmetic number, because the mean of its divisors is an integer number (5760016).

Almost surely, 2^11520031 is an apocalyptic number.

11520031 is a deficient number, since it is larger than the sum of its proper divisors (1).

11520031 is an equidigital number, since it uses as much as digits as its factorization.

11520031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 30, while the sum is 13.

The square root of 11520031 is about 3394.1171164237. The cubic root of 11520031 is about 225.8488495154.

Adding to 11520031 its reverse (13002511), we get a palindrome (24522542).

The spelling of 11520031 in words is "eleven million, five hundred twenty thousand, thirty-one".