Base | Representation |
---|---|
bin | 11010001100110100100111… |
… | …101100010110110100000111 |
3 | 120002222220122202122022011202 |
4 | 122030310213230112310013 |
5 | 110100413220420223331 |
6 | 1045024031121253115 |
7 | 33162055222106252 |
oct | 3214644754266407 |
9 | 502886582568152 |
10 | 115230343523591 |
11 | 33796a0696327a |
12 | 10b104b4a9419b |
13 | 4c3b236c7607a |
14 | 206526d6b6099 |
15 | d4c61423becb |
hex | 68cd27b16d07 |
115230343523591 has 2 divisors, whose sum is σ = 115230343523592. Its totient is φ = 115230343523590.
The previous prime is 115230343523521. The next prime is 115230343523593. The reversal of 115230343523591 is 195325343032511.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 115230343523591 - 238 = 114955465616647 is a prime.
Together with 115230343523593, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115230343523593) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57615171761795 + 57615171761796.
It is an arithmetic number, because the mean of its divisors is an integer number (57615171761796).
Almost surely, 2115230343523591 is an apocalyptic number.
115230343523591 is a deficient number, since it is larger than the sum of its proper divisors (1).
115230343523591 is an equidigital number, since it uses as much as digits as its factorization.
115230343523591 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458000, while the sum is 47.
The spelling of 115230343523591 in words is "one hundred fifteen trillion, two hundred thirty billion, three hundred forty-three million, five hundred twenty-three thousand, five hundred ninety-one".
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