Base | Representation |
---|---|
bin | 10000110001010001000… |
… | …101001001101111000101 |
3 | 11002011120112121212220111 |
4 | 100301101011021233011 |
5 | 122340114323243141 |
6 | 2241224402433021 |
7 | 146154555320251 |
oct | 20612105115705 |
9 | 4064515555814 |
10 | 1152411540421 |
11 | 40480a2a9059 |
12 | 167418362771 |
13 | 8489734469b |
14 | 3dac41bd261 |
15 | 1ee9bdeb381 |
hex | 10c51149bc5 |
1152411540421 has 2 divisors, whose sum is σ = 1152411540422. Its totient is φ = 1152411540420.
The previous prime is 1152411540353. The next prime is 1152411540439. The reversal of 1152411540421 is 1240451142511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1137272944900 + 15138595521 = 1066430^2 + 123039^2 .
It is a cyclic number.
It is not a de Polignac number, because 1152411540421 - 223 = 1152403151813 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1152411543421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 576205770210 + 576205770211.
It is an arithmetic number, because the mean of its divisors is an integer number (576205770211).
Almost surely, 21152411540421 is an apocalyptic number.
It is an amenable number.
1152411540421 is a deficient number, since it is larger than the sum of its proper divisors (1).
1152411540421 is an equidigital number, since it uses as much as digits as its factorization.
1152411540421 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6400, while the sum is 31.
Adding to 1152411540421 its reverse (1240451142511), we get a palindrome (2392862682932).
The spelling of 1152411540421 in words is "one trillion, one hundred fifty-two billion, four hundred eleven million, five hundred forty thousand, four hundred twenty-one".
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