Base | Representation |
---|---|
bin | 110101101010100010… |
… | …1110110101010101101 |
3 | 102000110120100112100111 |
4 | 1223111011312222231 |
5 | 3342010010400331 |
6 | 124535323500021 |
7 | 11216600542441 |
oct | 1532505665255 |
9 | 360416315314 |
10 | 115244231341 |
11 | 449694007a8 |
12 | 1a403087611 |
13 | ab37b2b585 |
14 | 581389c821 |
15 | 2ee76e3db1 |
hex | 1ad5176aad |
115244231341 has 2 divisors, whose sum is σ = 115244231342. Its totient is φ = 115244231340.
The previous prime is 115244231339. The next prime is 115244231357. The reversal of 115244231341 is 143132442511.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 97013560900 + 18230670441 = 311470^2 + 135021^2 .
It is a cyclic number.
It is not a de Polignac number, because 115244231341 - 21 = 115244231339 is a prime.
Together with 115244231339, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115244231371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57622115670 + 57622115671.
It is an arithmetic number, because the mean of its divisors is an integer number (57622115671).
Almost surely, 2115244231341 is an apocalyptic number.
It is an amenable number.
115244231341 is a deficient number, since it is larger than the sum of its proper divisors (1).
115244231341 is an equidigital number, since it uses as much as digits as its factorization.
115244231341 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 11520, while the sum is 31.
Adding to 115244231341 its reverse (143132442511), we get a palindrome (258376673852).
The spelling of 115244231341 in words is "one hundred fifteen billion, two hundred forty-four million, two hundred thirty-one thousand, three hundred forty-one".
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