Base | Representation |
---|---|
bin | 10101011101111001… |
… | …01000100101000111 |
3 | 1002202012102222001102 |
4 | 22232330220211013 |
5 | 142100404040111 |
6 | 5143342050315 |
7 | 555413302454 |
oct | 125674504507 |
9 | 32665388042 |
10 | 11525065031 |
11 | 4984664a37 |
12 | 229787999b |
13 | 111894740c |
14 | 7b490c82b |
15 | 476c0913b |
hex | 2aef28947 |
11525065031 has 2 divisors, whose sum is σ = 11525065032. Its totient is φ = 11525065030.
The previous prime is 11525065007. The next prime is 11525065033. The reversal of 11525065031 is 13056052511.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11525065031 is a prime.
It is a super-2 number, since 2×115250650312 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
Together with 11525065033, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 11525064985 and 11525065003.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11525065033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5762532515 + 5762532516.
It is an arithmetic number, because the mean of its divisors is an integer number (5762532516).
Almost surely, 211525065031 is an apocalyptic number.
11525065031 is a deficient number, since it is larger than the sum of its proper divisors (1).
11525065031 is an equidigital number, since it uses as much as digits as its factorization.
11525065031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4500, while the sum is 29.
The spelling of 11525065031 in words is "eleven billion, five hundred twenty-five million, sixty-five thousand, thirty-one".
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