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115254023 is a prime number
BaseRepresentation
bin1101101111010…
…10001100000111
322000212111210112
412313222030013
5214001112043
615234143235
72566433363
oct667521407
9260774715
10115254023
115a070065
1232721b1b
131ab54961
14114422a3
15a1b9518
hex6dea307

115254023 has 2 divisors, whose sum is σ = 115254024. Its totient is φ = 115254022.

The previous prime is 115253987. The next prime is 115254031. The reversal of 115254023 is 320452511.

It is a strong prime.

It is an emirp because it is prime and its reverse (320452511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 115254023 - 210 = 115252999 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 115254023.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115254053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57627011 + 57627012.

It is an arithmetic number, because the mean of its divisors is an integer number (57627012).

Almost surely, 2115254023 is an apocalyptic number.

115254023 is a deficient number, since it is larger than the sum of its proper divisors (1).

115254023 is an equidigital number, since it uses as much as digits as its factorization.

115254023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1200, while the sum is 23.

The square root of 115254023 is about 10735.6426449468. The cubic root of 115254023 is about 486.6522076666.

The spelling of 115254023 in words is "one hundred fifteen million, two hundred fifty-four thousand, twenty-three".