115254031 has 2 divisors, whose sum is σ = 115254032. Its totient is φ = 115254030.

The previous prime is 115254023. The next prime is 115254037. The reversal of 115254031 is 130452511.

It is a happy number.

115254031 is nontrivially palindromic in base 6.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 115254031 - 2³ = 115254023 is a prime.

It is a super-2 number, since 2×115254031² = 26566983323497922, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 115253993 and 115254011.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115254037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57627015 + 57627016.

It is an arithmetic number, because the mean of its divisors is an integer number (57627016).

Almost surely, 2^115254031 is an apocalyptic number.

115254031 is a deficient number, since it is larger than the sum of its proper divisors (1).

115254031 is an equidigital number, since it uses as much as digits as its factorization.

115254031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 600, while the sum is 22.

The square root of 115254031 is about 10735.6430175374. The cubic root of 115254031 is about 486.6522189264.

The spelling of 115254031 in words is "one hundred fifteen million, two hundred fifty-four thousand, thirty-one".