Base | Representation |
---|---|
bin | 1010011111001010100101… |
… | …0110000011011111100111 |
3 | 1111211022022200202110022102 |
4 | 2213302221112003133213 |
5 | 3002404013014302242 |
6 | 40305015350322315 |
7 | 2300024236242113 |
oct | 247625126033747 |
9 | 44738280673272 |
10 | 11530533353447 |
11 | 3746087528809 |
12 | 136284035939b |
13 | 65842b299474 |
14 | 2bc11b99c743 |
15 | 14ee07b6be32 |
hex | a7ca95837e7 |
11530533353447 has 2 divisors, whose sum is σ = 11530533353448. Its totient is φ = 11530533353446.
The previous prime is 11530533353411. The next prime is 11530533353509. The reversal of 11530533353447 is 74435333503511.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11530533353447 - 210 = 11530533352423 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11530533350447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5765266676723 + 5765266676724.
It is an arithmetic number, because the mean of its divisors is an integer number (5765266676724).
Almost surely, 211530533353447 is an apocalyptic number.
11530533353447 is a deficient number, since it is larger than the sum of its proper divisors (1).
11530533353447 is an equidigital number, since it uses as much as digits as its factorization.
11530533353447 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3402000, while the sum is 47.
Adding to 11530533353447 its reverse (74435333503511), we get a palindrome (85965866856958).
The spelling of 11530533353447 in words is "eleven trillion, five hundred thirty billion, five hundred thirty-three million, three hundred fifty-three thousand, four hundred forty-seven".
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