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1153133141 is a prime number
BaseRepresentation
bin100010010111011…
…0110101001010101
32222100211020021212
41010232312221111
54330200230031
6310231351205
740401320126
oct10456665125
92870736255
101153133141
11541a05aa6
12282222505
13154b95204
14ad21004d
156b37e12b
hex44bb6a55

1153133141 has 2 divisors, whose sum is σ = 1153133142. Its totient is φ = 1153133140.

The previous prime is 1153133117. The next prime is 1153133143. The reversal of 1153133141 is 1413313511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 899400100 + 253733041 = 29990^2 + 15929^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1153133141 is a prime.

It is a Sophie Germain prime.

Together with 1153133143, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1153133143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 576566570 + 576566571.

It is an arithmetic number, because the mean of its divisors is an integer number (576566571).

Almost surely, 21153133141 is an apocalyptic number.

It is an amenable number.

1153133141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1153133141 is an equidigital number, since it uses as much as digits as its factorization.

1153133141 is an evil number, because the sum of its binary digits is even.

The product of its digits is 540, while the sum is 23.

The square root of 1153133141 is about 33957.8141375442. The cubic root of 1153133141 is about 1048.6401568006.

Adding to 1153133141 its reverse (1413313511), we get a palindrome (2566446652).

The spelling of 1153133141 in words is "one billion, one hundred fifty-three million, one hundred thirty-three thousand, one hundred forty-one".