Base | Representation |
---|---|
bin | 110101101110010101… |
… | …1100010110100110111 |
3 | 102000210102221002112111 |
4 | 1223130223202310313 |
5 | 3342240104131210 |
6 | 125000112431451 |
7 | 11223005004034 |
oct | 1533453426467 |
9 | 360712832474 |
10 | 115371552055 |
11 | 44a24262731 |
12 | 1a439848587 |
13 | ab58319686 |
14 | 582676238b |
15 | 300399388a |
hex | 1adcae2d37 |
115371552055 has 4 divisors (see below), whose sum is σ = 138445862472. Its totient is φ = 92297241640.
The previous prime is 115371551983. The next prime is 115371552067. The reversal of 115371552055 is 550255173511.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 115371552055 - 215 = 115371519287 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 115371551999 and 115371552017.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11537155201 + ... + 11537155210.
It is an arithmetic number, because the mean of its divisors is an integer number (34611465618).
Almost surely, 2115371552055 is an apocalyptic number.
115371552055 is a deficient number, since it is larger than the sum of its proper divisors (23074310417).
115371552055 is an equidigital number, since it uses as much as digits as its factorization.
115371552055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23074310416.
The product of its (nonzero) digits is 131250, while the sum is 40.
The spelling of 115371552055 in words is "one hundred fifteen billion, three hundred seventy-one million, five hundred fifty-two thousand, fifty-five".
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