11540315413 has 4 divisors (see below), whose sum is σ = 12589435008. Its totient is φ = 10491195820.

The previous prime is 11540315401. The next prime is 11540315417. The reversal of 11540315413 is 31451304511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11540315413 - 2²¹ = 11538218261 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11540315417) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 524559781 + ... + 524559802.

It is an arithmetic number, because the mean of its divisors is an integer number (3147358752).

Almost surely, 2^11540315413 is an apocalyptic number.

It is an amenable number.

11540315413 is a deficient number, since it is larger than the sum of its proper divisors (1049119595).

11540315413 is a wasteful number, since it uses less digits than its factorization.

11540315413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1049119594.

The product of its (nonzero) digits is 3600, while the sum is 28.

Adding to 11540315413 its reverse (31451304511), we get a palindrome (42991619924).

It can be divided in two parts, 115403 and 15413, that added together give a triangular number (130816 = T₅₁₁).

The spelling of 11540315413 in words is "eleven billion, five hundred forty million, three hundred fifteen thousand, four hundred thirteen".