Search a number
-
+
115513431531420 = 223513231538383537
BaseRepresentation
bin11010010000111100010001…
…000011011001111110011100
3120010222222100122200010001110
4122100330101003121332130
5110120033001433001140
61045402045435542020
733221366342345166
oct3220742103317634
9503888318603043
10115513431531420
1133895a7574153a
1210b5733a5ba910
134c5bb400b6800
142074c466c7936
15d54b81d0a380
hex690f110d9f9c

115513431531420 has 576 divisors, whose sum is σ = 372792759865344. Its totient is φ = 26672069099520.

The previous prime is 115513431531401. The next prime is 115513431531481. The reversal of 115513431531420 is 24135134315511.

It is a Harshad number since it is a multiple of its sum of digits (39).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 1382739892 + ... + 1382823428.

It is an arithmetic number, because the mean of its divisors is an integer number (647209652544).

Almost surely, 2115513431531420 is an apocalyptic number.

115513431531420 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 115513431531420, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (186396379932672).

115513431531420 is an abundant number, since it is smaller than the sum of its proper divisors (257279328333924).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

115513431531420 is a wasteful number, since it uses less digits than its factorization.

115513431531420 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 83742 (or 83727 counting only the distinct ones).

The product of its (nonzero) digits is 108000, while the sum is 39.

Adding to 115513431531420 its reverse (24135134315511), we get a palindrome (139648565846931).

The spelling of 115513431531420 in words is "one hundred fifteen trillion, five hundred thirteen billion, four hundred thirty-one million, five hundred thirty-one thousand, four hundred twenty".