Base | Representation |
---|---|
bin | 10000110011111001101… |
… | …100001010111101010111 |
3 | 11002102212200111212020201 |
4 | 100303321230022331113 |
5 | 122411413011410320 |
6 | 2242413213441331 |
7 | 146314634611243 |
oct | 20637154127527 |
9 | 4072780455221 |
10 | 1155240341335 |
11 | 405a31068053 |
12 | 167a877a0247 |
13 | 84c28416b92 |
14 | 3dcb1b7d423 |
15 | 200b542470a |
hex | 10cf9b0af57 |
1155240341335 has 16 divisors (see below), whose sum is σ = 1391285769120. Its totient is φ = 920865604480.
The previous prime is 1155240341257. The next prime is 1155240341401. The reversal of 1155240341335 is 5331430425511.
It is not a de Polignac number, because 1155240341335 - 229 = 1154703470423 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1155240341294 and 1155240341303.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1582749 + ... + 2194441.
It is an arithmetic number, because the mean of its divisors is an integer number (86955360570).
Almost surely, 21155240341335 is an apocalyptic number.
1155240341335 is a deficient number, since it is larger than the sum of its proper divisors (236045427785).
1155240341335 is an equidigital number, since it uses as much as digits as its factorization.
1155240341335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 613058.
The product of its (nonzero) digits is 108000, while the sum is 37.
Adding to 1155240341335 its reverse (5331430425511), we get a palindrome (6486670766846).
The spelling of 1155240341335 in words is "one trillion, one hundred fifty-five billion, two hundred forty million, three hundred forty-one thousand, three hundred thirty-five".
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