11563105314135 has 128 divisors (see below), whose sum is σ = 19123352985600. Its totient is φ = 5964151564800.

The previous prime is 11563105314113. The next prime is 11563105314143. The reversal of 11563105314135 is 53141350136511.

11563105314135 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 11563105314135 - 2¹² = 11563105310039 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11563105314093 and 11563105314102.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 13461123336 + ... + 13461124194.

It is an arithmetic number, because the mean of its divisors is an integer number (149401195200).

Almost surely, 2^{11563105314135} is an apocalyptic number.

11563105314135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

11563105314135 is a deficient number, since it is larger than the sum of its proper divisors (7560247671465).

11563105314135 is a wasteful number, since it uses less digits than its factorization.

11563105314135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2021.

The product of its (nonzero) digits is 81000, while the sum is 39.

The spelling of 11563105314135 in words is "eleven trillion, five hundred sixty-three billion, one hundred five million, three hundred fourteen thousand, one hundred thirty-five".