11575308343 has 2 divisors, whose sum is σ = 11575308344. Its totient is φ = 11575308342.

The previous prime is 11575308323. The next prime is 11575308359. The reversal of 11575308343 is 34380357511.

It is a happy number.

11575308343 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (34380357511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11575308343 - 2⁹ = 11575307831 is a prime.

It is a super-4 number, since 4×11575308343⁴ (a number of 41 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11575308296 and 11575308305.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11575308323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5787654171 + 5787654172.

It is an arithmetic number, because the mean of its divisors is an integer number (5787654172).

Almost surely, 2^11575308343 is an apocalyptic number.

11575308343 is a deficient number, since it is larger than the sum of its proper divisors (1).

11575308343 is an equidigital number, since it uses as much as digits as its factorization.

11575308343 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 151200, while the sum is 40.

The spelling of 11575308343 in words is "eleven billion, five hundred seventy-five million, three hundred eight thousand, three hundred forty-three".