11713345442253 has 48 divisors (see below), whose sum is σ = 20824179667200. Its totient is φ = 6178333093632.

The previous prime is 11713345442237. The next prime is 11713345442263. The reversal of 11713345442253 is 35224454331711.

11713345442253 is a `hidden beast` number, since 1 + 1 + 7 + 1 + 3 + 34 + 544 + 22 + 53 = 666.

It is not a de Polignac number, because 11713345442253 - 2⁴ = 11713345442237 is a prime.

It is a super-2 number, since 2×11713345442253² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11713345442199 and 11713345442208.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11713345442203) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 45571225 + ... + 45827537.

It is an arithmetic number, because the mean of its divisors is an integer number (433837076400).

Almost surely, 2^{11713345442253} is an apocalyptic number.

11713345442253 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11713345442253 is a deficient number, since it is larger than the sum of its proper divisors (9110834224947).

11713345442253 is a wasteful number, since it uses less digits than its factorization.

11713345442253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 312138 (or 312135 counting only the distinct ones).

The product of its digits is 1209600, while the sum is 45.

Adding to 11713345442253 its reverse (35224454331711), we get a palindrome (46937799773964).

The spelling of 11713345442253 in words is "eleven trillion, seven hundred thirteen billion, three hundred forty-five million, four hundred forty-two thousand, two hundred fifty-three".