117148133 has 4 divisors (see below), whose sum is σ = 117562368. Its totient is φ = 116733900.

The previous prime is 117148103. The next prime is 117148153. The reversal of 117148133 is 331841711.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 331841711 = 1117 ⋅297083.

It is a cyclic number.

It is not a de Polignac number, because 117148133 - 2⁶ = 117148069 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 117148096 and 117148105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (117148103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 206693 + ... + 207258.

It is an arithmetic number, because the mean of its divisors is an integer number (29390592).

Almost surely, 2^117148133 is an apocalyptic number.

It is an amenable number.

117148133 is a deficient number, since it is larger than the sum of its proper divisors (414235).

117148133 is an equidigital number, since it uses as much as digits as its factorization.

117148133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 414234.

The product of its digits is 2016, while the sum is 29.

The square root of 117148133 is about 10823.4991107312. The cubic root of 117148133 is about 489.3036519976.

Adding to 117148133 its reverse (331841711), we get a palindrome (448989844).

The spelling of 117148133 in words is "one hundred seventeen million, one hundred forty-eight thousand, one hundred thirty-three".