Base | Representation |
---|---|
bin | 1010101010101010011001… |
… | …0110101100111111101000 |
3 | 1112112012011002100102222112 |
4 | 2222222212112230333220 |
5 | 3014123022212444100 |
6 | 40535443105541452 |
7 | 2320216024340126 |
oct | 252524626547750 |
9 | 45465132312875 |
10 | 11728051687400 |
11 | 3811925478534 |
12 | 1394b84944888 |
13 | 670c48408199 |
14 | 2c78d8242916 |
15 | 1551182d7b35 |
hex | aaaa65acfe8 |
11728051687400 has 24 divisors (see below), whose sum is σ = 27267720173670. Its totient is φ = 4691220674880.
The previous prime is 11728051687381. The next prime is 11728051687463. The reversal of 11728051687400 is 478615082711.
It is a happy number.
It can be written as a sum of positive squares in 3 ways, for example, as 6193597825636 + 5534453861764 = 2488694^2 + 2352542^2 .
It is a super-3 number, since 3×117280516874003 (a number of 40 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (50).
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 29320129019 + ... + 29320129418.
Almost surely, 211728051687400 is an apocalyptic number.
11728051687400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11728051687400 is an abundant number, since it is smaller than the sum of its proper divisors (15539668486270).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11728051687400 is a wasteful number, since it uses less digits than its factorization.
11728051687400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 58640258453 (or 58640258444 counting only the distinct ones).
The product of its (nonzero) digits is 752640, while the sum is 50.
The spelling of 11728051687400 in words is "eleven trillion, seven hundred twenty-eight billion, fifty-one million, six hundred eighty-seven thousand, four hundred".
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