Base | Representation |
---|---|
bin | 11010110010010101101011… |
… | …100011000011001111010011 |
3 | 120110010101020021222111202212 |
4 | 122302111223203003033103 |
5 | 110420133212322444103 |
6 | 1054320243242302335 |
7 | 33546244343201612 |
oct | 3262255343031723 |
9 | 513111207874685 |
10 | 117808462312403 |
11 | 345a0319795845 |
12 | 1126809b7b79ab |
13 | 50973a0b074a5 |
14 | 2113d6234b879 |
15 | d947060c07d8 |
hex | 6b256b8c33d3 |
117808462312403 has 4 divisors (see below), whose sum is σ = 122930569369488. Its totient is φ = 112686355255320.
The previous prime is 117808462312367. The next prime is 117808462312417. The reversal of 117808462312403 is 304213264808711.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 117808462312403 - 28 = 117808462312147 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (117808462312603) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2561053528508 + ... + 2561053528553.
It is an arithmetic number, because the mean of its divisors is an integer number (30732642342372).
Almost surely, 2117808462312403 is an apocalyptic number.
117808462312403 is a deficient number, since it is larger than the sum of its proper divisors (5122107057085).
117808462312403 is an equidigital number, since it uses as much as digits as its factorization.
117808462312403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5122107057084.
The product of its (nonzero) digits is 1548288, while the sum is 50.
The spelling of 117808462312403 in words is "one hundred seventeen trillion, eight hundred eight billion, four hundred sixty-two million, three hundred twelve thousand, four hundred three".
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