Base | Representation |
---|---|
bin | 1010110011000110110110… |
… | …0001110010101111101010 |
3 | 1120001001121122111010102220 |
4 | 2230301231201302233222 |
5 | 3024012131024300130 |
6 | 41130234521134510 |
7 | 2333543105601534 |
oct | 254615541625752 |
9 | 46031548433386 |
10 | 11873127181290 |
11 | 3868401842321 |
12 | 13b911232a436 |
13 | 68182866c0ab |
14 | 2d093b984854 |
15 | 158ca98c4410 |
hex | acc6d872bea |
11873127181290 has 64 divisors (see below), whose sum is σ = 28842511276800. Its totient is φ = 3127761345024.
The previous prime is 11873127181277. The next prime is 11873127181297. The reversal of 11873127181290 is 9218172137811.
It is a happy number.
It is a super-2 number, since 2×118731271812902 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (11873127181297) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3433545 + ... + 5961164.
It is an arithmetic number, because the mean of its divisors is an integer number (450664238700).
Almost surely, 211873127181290 is an apocalyptic number.
11873127181290 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11873127181290 is an abundant number, since it is smaller than the sum of its proper divisors (16969384095510).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11873127181290 is a wasteful number, since it uses less digits than its factorization.
11873127181290 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9395231.
The product of its (nonzero) digits is 338688, while the sum is 51.
The spelling of 11873127181290 in words is "eleven trillion, eight hundred seventy-three billion, one hundred twenty-seven million, one hundred eighty-one thousand, two hundred ninety".
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