Base | Representation |
---|---|
bin | 1010110111000110100010… |
… | …0011110101000000111111 |
3 | 1120021121210000110111111122 |
4 | 2231301220203311000333 |
5 | 3031123212401234120 |
6 | 41221545331341155 |
7 | 2341523012202200 |
oct | 255615043650077 |
9 | 46247700414448 |
10 | 11941763305535 |
11 | 3894523079348 |
12 | 140a4884517bb |
13 | 68814637566b |
14 | 2d3dad3ad5a7 |
15 | 15a9753c8a25 |
hex | adc688f503f |
11941763305535 has 48 divisors (see below), whose sum is σ = 16684267032576. Its totient is φ = 8181498975552.
The previous prime is 11941763305531. The next prime is 11941763305541. The reversal of 11941763305535 is 53550336714911.
It is not a de Polignac number, because 11941763305535 - 22 = 11941763305531 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11941763305531) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2377414034 + ... + 2377419056.
It is an arithmetic number, because the mean of its divisors is an integer number (347588896512).
Almost surely, 211941763305535 is an apocalyptic number.
11941763305535 is a deficient number, since it is larger than the sum of its proper divisors (4742503727041).
11941763305535 is a wasteful number, since it uses less digits than its factorization.
11941763305535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11572 (or 11565 counting only the distinct ones).
The product of its (nonzero) digits is 5103000, while the sum is 53.
The spelling of 11941763305535 in words is "eleven trillion, nine hundred forty-one billion, seven hundred sixty-three million, three hundred five thousand, five hundred thirty-five".
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