119813 has 2 divisors, whose sum is σ = 119814. Its totient is φ = 119812.

The previous prime is 119809. The next prime is 119827. The reversal of 119813 is 318911.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 103684 + 16129 = 322^2 + 127^2 .

It is an emirp because it is prime and its reverse (318911) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 119813 - 2² = 119809 is a prime.

It is a plaindrome in base 15.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (119513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (7) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59906 + 59907.

It is an arithmetic number, because the mean of its divisors is an integer number (59907).

2¹¹⁹⁸¹³ is an apocalyptic number.

It is an amenable number.

119813 is a deficient number, since it is larger than the sum of its proper divisors (1).

119813 is an equidigital number, since it uses as much as digits as its factorization.

119813 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 216, while the sum is 23.

The square root of 119813 is about 346.1401450280. The cubic root of 119813 is about 49.2986069631.

The spelling of 119813 in words is "one hundred nineteen thousand, eight hundred thirteen".