11984023 has 2 divisors, whose sum is σ = 11984024. Its totient is φ = 11984022.

The previous prime is 11984017. The next prime is 11984029. The reversal of 11984023 is 32048911.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (11984017) and next prime (11984029).

It is an emirp because it is prime and its reverse (32048911) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11984023 - 2²¹ = 9886871 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11983982 and 11984000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11984029) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5992011 + 5992012.

It is an arithmetic number, because the mean of its divisors is an integer number (5992012).

Almost surely, 2^11984023 is an apocalyptic number.

11984023 is a deficient number, since it is larger than the sum of its proper divisors (1).

11984023 is an equidigital number, since it uses as much as digits as its factorization.

11984023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 28.

The square root of 11984023 is about 3461.7947657249. The cubic root of 11984023 is about 228.8411972759.

The spelling of 11984023 in words is "eleven million, nine hundred eighty-four thousand, twenty-three".