Base | Representation |
---|---|
bin | 10110010101100111… |
… | …11101101101001101 |
3 | 1010221210002212210102 |
4 | 23022303331231031 |
5 | 144030043214232 |
6 | 5302002020445 |
7 | 603121013132 |
oct | 131263755515 |
9 | 33853085712 |
10 | 11992554317 |
11 | 50a4536617 |
12 | 23a8347725 |
13 | 11917587b3 |
14 | 81aa40589 |
15 | 4a2c9e662 |
hex | 2cacfdb4d |
11992554317 has 2 divisors, whose sum is σ = 11992554318. Its totient is φ = 11992554316.
The previous prime is 11992554283. The next prime is 11992554319. The reversal of 11992554317 is 71345529911.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9782990281 + 2209564036 = 98909^2 + 47006^2 .
It is a cyclic number.
It is not a de Polignac number, because 11992554317 - 230 = 10918812493 is a prime.
Together with 11992554319, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11992554319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5996277158 + 5996277159.
It is an arithmetic number, because the mean of its divisors is an integer number (5996277159).
Almost surely, 211992554317 is an apocalyptic number.
It is an amenable number.
11992554317 is a deficient number, since it is larger than the sum of its proper divisors (1).
11992554317 is an equidigital number, since it uses as much as digits as its factorization.
11992554317 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 340200, while the sum is 47.
The spelling of 11992554317 in words is "eleven billion, nine hundred ninety-two million, five hundred fifty-four thousand, three hundred seventeen".
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