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1200010212110 = 25120001021211
BaseRepresentation
bin10001011101100110001…
…011101011001100001110
311020201102202220221100202
4101131212023223030032
5124130110103241420
62315135503253502
7152461241334653
oct21354613531416
94221382827322
101200010212110
11422a15531656
121746a0baa292
1389211751c88
144211ba25c2a
1521335a56575
hex117662eb30e

1200010212110 has 8 divisors (see below), whose sum is σ = 2160018381816. Its totient is φ = 480004084840.

The previous prime is 1200010212097. The next prime is 1200010212151. The reversal of 1200010212110 is 112120100021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 1200010212091 and 1200010212100.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60000510596 + ... + 60000510615.

It is an arithmetic number, because the mean of its divisors is an integer number (270002297727).

Almost surely, 21200010212110 is an apocalyptic number.

1200010212110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1200010212110 is a deficient number, since it is larger than the sum of its proper divisors (960008169706).

1200010212110 is a wasteful number, since it uses less digits than its factorization.

1200010212110 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 120001021218.

The product of its (nonzero) digits is 8, while the sum is 11.

Adding to 1200010212110 its reverse (112120100021), we get a palindrome (1312130312131).

The spelling of 1200010212110 in words is "one trillion, two hundred billion, ten million, two hundred twelve thousand, one hundred ten".

Divisors: 1 2 5 10 120001021211 240002042422 600005106055 1200010212110