12000311022013 has 4 divisors (see below), whose sum is σ = 12522063675168. Its totient is φ = 11478558368860.

The previous prime is 12000311021999. The next prime is 12000311022067. The reversal of 12000311022013 is 31022011300021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12000311022013 - 2³³ = 11991721087421 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12000311020013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 260876326543 + ... + 260876326588.

It is an arithmetic number, because the mean of its divisors is an integer number (3130515918792).

Almost surely, 2^{12000311022013} is an apocalyptic number.

It is an amenable number.

12000311022013 is a deficient number, since it is larger than the sum of its proper divisors (521752653155).

12000311022013 is an equidigital number, since it uses as much as digits as its factorization.

12000311022013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 521752653154.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 12000311022013 its reverse (31022011300021), we get a palindrome (43022322322034).

The spelling of 12000311022013 in words is "twelve trillion, three hundred eleven million, twenty-two thousand, thirteen".