1200047853 has 4 divisors (see below), whose sum is σ = 1600063808. Its totient is φ = 800031900.

The previous prime is 1200047831. The next prime is 1200047861. The reversal of 1200047853 is 3587400021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1200047853 - 2²⁸ = 931612397 is a prime.

It is a super-3 number, since 3×1200047853³ (a number of 28 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1200047853.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1200043853) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 200007973 + ... + 200007978.

It is an arithmetic number, because the mean of its divisors is an integer number (400015952).

Almost surely, 2^1200047853 is an apocalyptic number.

It is an amenable number.

1200047853 is a deficient number, since it is larger than the sum of its proper divisors (400015955).

1200047853 is an equidigital number, since it uses as much as digits as its factorization.

1200047853 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 400015954.

The product of its (nonzero) digits is 6720, while the sum is 30.

The square root of 1200047853 is about 34641.7068430526. The cubic root of 1200047853 is about 1062.6726943839.

Adding to 1200047853 its reverse (3587400021), we get a palindrome (4787447874).

The spelling of 1200047853 in words is "one billion, two hundred million, forty-seven thousand, eight hundred fifty-three".