Base | Representation |
---|---|
bin | 1010111010100011100101… |
… | …0011110001100100101000 |
3 | 1120111021221022010111011201 |
4 | 2232220321103301210220 |
5 | 3033111223112010440 |
6 | 41305121305133544 |
7 | 2346023306544442 |
oct | 256507123614450 |
9 | 46437838114151 |
10 | 12001100110120 |
11 | 3907702164920 |
12 | 1419a8818a2b4 |
13 | 6909115ab714 |
14 | 2d6bdbb49492 |
15 | 15c2997c919a |
hex | aea394f1928 |
12001100110120 has 128 divisors (see below), whose sum is σ = 30475302624000. Its totient is φ = 4213235783680.
The previous prime is 12001100110079. The next prime is 12001100110141. The reversal of 12001100110120 is 2101100110021.
It is a super-2 number, since 2×120011001101202 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (10).
It is a junction number, because it is equal to n+sod(n) for n = 12001100110097 and 12001100110106.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 226884636 + ... + 226937524.
It is an arithmetic number, because the mean of its divisors is an integer number (238088301750).
Almost surely, 212001100110120 is an apocalyptic number.
12001100110120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 12001100110120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15237651312000).
12001100110120 is an abundant number, since it is smaller than the sum of its proper divisors (18474202513880).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12001100110120 is a wasteful number, since it uses less digits than its factorization.
12001100110120 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 70723 (or 70719 counting only the distinct ones).
The product of its (nonzero) digits is 4, while the sum is 10.
Adding to 12001100110120 its reverse (2101100110021), we get a palindrome (14102200220141).
Subtracting from 12001100110120 its reverse (2101100110021), we obtain a palindrome (9900000000099).
The spelling of 12001100110120 in words is "twelve trillion, one billion, one hundred million, one hundred ten thousand, one hundred twenty".
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