Base | Representation |
---|---|
bin | 1010111010100011111101… |
… | …0100101001001010011001 |
3 | 1120111022012022222021121011 |
4 | 2232220333110221022121 |
5 | 3033111424424013423 |
6 | 41305135311413521 |
7 | 2346025643240332 |
oct | 256507724511231 |
9 | 46438168867534 |
10 | 12001201001113 |
11 | 3907754104805 |
12 | 1419ab5b242a1 |
13 | 69092947492c |
14 | 2d6c0b2cd289 |
15 | 15c2a35a7b0d |
hex | aea3f529299 |
12001201001113 has 2 divisors, whose sum is σ = 12001201001114. Its totient is φ = 12001201001112.
The previous prime is 12001201001087. The next prime is 12001201001123. The reversal of 12001201001113 is 31110010210021.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6721927358224 + 5279273642889 = 2592668^2 + 2297667^2 .
It is an emirp because it is prime and its reverse (31110010210021) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12001201001113 is a prime.
It is a super-3 number, since 3×120012010011133 (a number of 40 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12001201001093 and 12001201001102.
It is not a weakly prime, because it can be changed into another prime (12001201001123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6000600500556 + 6000600500557.
It is an arithmetic number, because the mean of its divisors is an integer number (6000600500557).
Almost surely, 212001201001113 is an apocalyptic number.
It is an amenable number.
12001201001113 is a deficient number, since it is larger than the sum of its proper divisors (1).
12001201001113 is an equidigital number, since it uses as much as digits as its factorization.
12001201001113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12, while the sum is 13.
Adding to 12001201001113 its reverse (31110010210021), we get a palindrome (43111211211134).
The spelling of 12001201001113 in words is "twelve trillion, one billion, two hundred one million, one thousand, one hundred thirteen".
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