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12001201200022 = 217425382994711
BaseRepresentation
bin1010111010100011111101…
…0101011001101110010110
31120111022012100100101110011
42232220333111121232112
53033111430001400042
641305135315550434
72346025645026256
oct256507725315626
946438170311404
1012001201200022
1139077542301a1
121419ab5bbb41a
13690929514328
142d6c0b341966
1515c2a35e6a17
hexaea3f559b96

12001201200022 has 16 divisors (see below), whose sum is σ = 19065213261792. Its totient is φ = 5646296110720.

The previous prime is 12001201200013. The next prime is 12001201200041. The reversal of 12001201200022 is 22000210210021.

It is a happy number.

It is a junction number, because it is equal to n+sod(n) for n = 12001201199975 and 12001201200011.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 41352754 + ... + 41641957.

It is an arithmetic number, because the mean of its divisors is an integer number (1191575828862).

Almost surely, 212001201200022 is an apocalyptic number.

12001201200022 is a deficient number, since it is larger than the sum of its proper divisors (7064012061770).

12001201200022 is a wasteful number, since it uses less digits than its factorization.

12001201200022 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 82998983.

The product of its (nonzero) digits is 32, while the sum is 13.

Adding to 12001201200022 its reverse (22000210210021), we get a palindrome (34001411410043).

Subtracting 12001201200022 from its reverse (22000210210021), we obtain a palindrome (9999009009999).

The spelling of 12001201200022 in words is "twelve trillion, one billion, two hundred one million, two hundred thousand, twenty-two".

Divisors: 1 2 17 34 4253 8506 72301 144602 82994711 165989422 1410910087 2821820174 352976505883 705953011766 6000600600011 12001201200022